1; \(P=\left(\frac{\sqrt{x}+2}{\sqrt{x}-2}-\frac{\sqrt{x}}{\sqrt{x}+2}+\frac{3\sqrt{x}+10}{4-x}\right):\frac{3}{1-\sqrt{x}}\)
\(=\frac{\left(\sqrt{x}+2\right)^2-\sqrt{x}\left(\sqrt{x}-2\right)-3\sqrt{x}-10}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\cdot\frac{1-\sqrt{x}}{3}\)
\(=\frac{x+4\sqrt{x}+4-x+2\sqrt{x}-3\sqrt{x}-10}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\cdot\frac{-\left(\sqrt{x}-1\right)}{3}\)
\(=\frac{3\sqrt{x}-6}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\cdot\frac{-\left(\sqrt{x}-1\right)}{3}=\frac{3\left(\sqrt{x}-2\right)\cdot\left(-1\right)\cdot\left(\sqrt{x}-1\right)}{3\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\)
\(=\frac{-\sqrt{x}+1}{\sqrt{x}+2}\)
2: \(P=-\frac13\)
=>\(\frac{-\sqrt{x}+1}{\sqrt{x}+2}=\frac{-1}{3}\)
=>\(\frac{\sqrt{x}-1}{\sqrt{x}+2}=\frac13\)
=>\(3\left(\sqrt{x}-1\right)=\sqrt{x}+2\)
=>\(3\sqrt{x}-3=\sqrt{x}+2\)
=>\(2\sqrt{x}=5\)
=>\(\sqrt{x}=\frac52\)
=>x=25/4(nhận)
