a, BC=HB+HC=4+9=13
Áp dụng HTL ta có: \(BH.BC=AB^2\Rightarrow AB=\sqrt{4.13}\Rightarrow AB=2\sqrt{13}\)
Áp dụng HTL ta có: \(BH.HC=AH^2\Rightarrow AH=\sqrt{4.9}\Rightarrow AH=6\left(cm\right)\)
b,ta có: \(\widehat{HEA}=90^o;\widehat{BAC}=90^o;\widehat{AFH}=90^o\)\(\Rightarrow AEHF\) là hcn
\(\Rightarrow AH=EF\)
Diện tích AEHF là: \(AE.AF=EF^2=AH^2=6^2=36\left(cm^2\right)\)