b) \(2x-\sqrt{x^2+4x+4}=1\\ \Rightarrow\left|x+2\right|=2x-1\\ \Rightarrow\left[{}\begin{matrix}x+2=2x-1\\x+2=1-2x\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{1}{3}\end{matrix}\right.\)
c) \(\left(\sqrt{x}-2\right)\left(\sqrt{x}+3\right)=x-5\sqrt{x}\\ \Rightarrow x-2\sqrt{x}+3\sqrt{x}-6=x-5\sqrt{x}\\ \Rightarrow6\sqrt{x}-6=0\\ \Rightarrow\sqrt{x}=1\\ \Rightarrow x=1\)
â) ĐKXĐ: \(x\ge2\)
\(\sqrt{25x-50}-\sqrt{x-2}=\sqrt{9x-18}+\sqrt{10}\\ \Rightarrow5\sqrt{x-2}-\sqrt{x-2}=3\sqrt{x-2}+\sqrt{10}\\ \Rightarrow\sqrt{x-2}=\sqrt{10}\\ \Rightarrow x-2=10\\ \Rightarrow x=12\)
