\(\dfrac{4+2\sqrt{3}}{2+\sqrt{3}+1}+\dfrac{4-2\sqrt{3}}{2-\sqrt{3}+1}\)
\(=\dfrac{4+2\sqrt{3}}{3+\sqrt{3}}+\dfrac{4-2\sqrt{3}}{3-\sqrt{3}}\)
\(=\dfrac{12-4\sqrt{3}+6\sqrt{3}-6+12+4\sqrt{3}-6\sqrt{3}-6}{\left(3+\sqrt{3}\right)\left(3-\sqrt{3}\right)}\)
\(=\dfrac{12}{9-3}=2\)