Bài 2:
1: Ta có: \(\sqrt{x^2-4x+4}=3\)
\(\Leftrightarrow\left|x-2\right|=3\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=3\\x-2=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-1\end{matrix}\right.\)
2: Ta có: \(\dfrac{\sqrt{3}}{3}x=\sqrt{12}+5\sqrt{3}-\sqrt{243}\)
\(\Leftrightarrow x\cdot\dfrac{\sqrt{3}}{3}=2\sqrt{3}+5\sqrt{3}-9\sqrt{3}\)
\(\Leftrightarrow x\cdot\dfrac{\sqrt{3}}{3}=-2\sqrt{3}\)
\(\Leftrightarrow x=-6\)
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