2: Ta có: \(\sqrt[3]{x^2+2}=3\)
\(\Leftrightarrow x^2+2=27\)
hay \(x\in\left\{5;-5\right\}\)
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2: Ta có: \(\sqrt[3]{x^2+2}=3\)
\(\Leftrightarrow x^2+2=27\)
hay \(x\in\left\{5;-5\right\}\)