Sửa đề: \(\sqrt{9x+9}+3\cdot\sqrt{4x+4}-\sqrt{25x+25}=8\)
ĐKXĐ: x>=-1
Ta có: \(\sqrt{9x+9}+3\cdot\sqrt{4x+4}-\sqrt{25x+25}=8\)
=>\(3\cdot\sqrt{x+1}+3\cdot2\cdot\sqrt{x+1}-5\cdot\sqrt{x+1}=8\)
=>\(4\cdot\sqrt{x+1}=8\)
=>\(\sqrt{x+1}=2\)
=>x+1=4
=>x=3(nhận)

