ĐKXĐ: x>=1/4
Ta có: \(\sqrt{4x-1}+\sqrt{34x-3}=\sqrt{33x+2}+\sqrt{3x+4}\)
=>\(\sqrt{4x-1}-\sqrt{3x+4}=\sqrt{33x+2}-\sqrt{34x-3}\)
=>\(\frac{4x-1-3x-4}{\sqrt{4x-1}+\sqrt{3x+4}}=\frac{33x+2-34x+3}{\sqrt{33x+2}+\sqrt{34x-3}}\)
=>\(\frac{x-5}{\sqrt{4x-1}+\sqrt{3x+4}}=\frac{-\left(x-5\right)}{\sqrt{33x+2}+\sqrt{34x-3}}\)
=>\(\left(x-5\right)\left(\frac{1}{\sqrt{4x-1}+\sqrt{3x+4}}+\frac{1}{\sqrt{33x+2}+\sqrt{34x-3}}\right)=0\)
=>x-5=0
=>x=5(nhận)
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