Question

Answer 1

d: Ta có: \(\left(\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\right)^2\)

\(=3-\sqrt{5}+3+\sqrt{5}+2\cdot\sqrt{9-5}\)

\(=6+2\cdot2=10\)

Answer 2

c: Ta có: \(\left(2\sqrt{3}-\sqrt{7}\right)\left(2\sqrt{3}+\sqrt{7}\right)-\left(\sqrt{3}+\sqrt{2}\right)^2\)

\(=12-7-5-2\sqrt{6}\)

\(=-2\sqrt{6}\)