a: Ta có: \(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
\(\Leftrightarrow7x-7=6x+30\)
hay x=37
\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
\(\Rightarrow7x-7=6x+30\)
\(\Rightarrow x=37\)
\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\Leftrightarrow6x+30=7x-7\Leftrightarrow x=37\)
(x-1)7=(x+5)6
7x-7=6x+30
7x-6x=30+7
x=37
\(a) \dfrac{x-1}{x+5} <=>7x - 7 = 6x + 30 => x=....\)
