\(\dfrac{8}{x-5}=\dfrac{3}{x+1}\)
\(\Rightarrow8\left(x+1\right)=3\left(x-5\right)\)
\(\Rightarrow8x+8=3x-15\)
\(\Rightarrow5x=-23\)
\(\Rightarrow x=-\dfrac{23}{5}\) ( thỏa mãn đk )
Ta có: \(\dfrac{8}{x-5}=\dfrac{3}{x+1}\)
\(\Leftrightarrow8x+8=3x-15\)
\(\Leftrightarrow5x=-23\)
hay \(x=-\dfrac{23}{5}\)
