Question

Answer 1

1. \(x^2-4x-5=\left(x^2+x\right)-\left(5x+5\right)=x\left(x+1\right)-5\left(x+1\right)=\left(x-5\right)\left(x+1\right)\)

2. \(x^2-x-6=\left(x^2-2x\right)+\left(3x-6\right)=x\left(x-2\right)+3\left(x-2\right)=\left(x-2\right)\left(x+3\right)\)

3, \(2x^2-7x+5=\left(2x^2-2x\right)-\left(5x-5\right)=2x\left(x-1\right)-5\left(x-1\right)=\left(x-1\right)\left(2x-5\right)\)

4, \(7x^2+3x-10=\left(7x^2-7x\right)+\left(10x-10\right)=7x\left(x-1\right)+10\left(x-1\right)=\left(x-1\right)\left(7x+10\right)\)

Answer 2

1: \(x^2-4x-5=\left(x-5\right)\left(x+1\right)\)

2: \(x^2-x-6=\left(x-3\right)\left(x+2\right)\)

3: \(2x^2-7x+5=\left(x-1\right)\left(2x-5\right)\)

4: \(7x^2+3x-10=\left(x-1\right)\left(7x+10\right)\)