Câu hỏi của Duy Nguyễn

a: Ta có: \(P=\dfrac{\sqrt{x}-3}{2-\sqrt{x}}+\dfrac{\sqrt{x}-2}{\sqrt{x}+3}-\dfrac{9-x}{x+\sqrt{x}-6}\)\(=\dfrac{-x+9+x-4\sqrt{x}+4-9+x}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}\)\(=\dfrac{x-4\sqrt{x}+4}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}\)\(=\dfrac{\sqrt{x}-2}{\sqrt{x}+3}\)Câu trả lời: a: Ta có: \(P=\dfrac{\sqrt{x}-3}{2-\sqrt{x}}+\dfrac{\sqrt{x}-2}{\sqrt{x}+3}-\dfrac{9-x}{x+\sqrt{x}-6}\)\(=\dfrac{-x+9+x-4\sqrt{x}+4-9+x}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}\)\(=\dfrac{x-4\sqrt{x}+4}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}\)\(=\dfrac{\sqrt{x}-2}{\sqrt{x}+3}\)