a: Ta có: \(\sqrt{\dfrac{9}{16}:\dfrac{25}{36}}-\sqrt{\dfrac{49}{8}}:\sqrt{3\dfrac{1}{8}}\)
\(=\dfrac{3}{4}:\dfrac{5}{6}-\dfrac{7\sqrt{2}}{4}:\dfrac{5\sqrt{2}}{4}\)
\(=\dfrac{3}{4}\cdot\dfrac{6}{5}-\dfrac{7}{5}\)
\(=\dfrac{9}{10}-\dfrac{14}{10}=-\dfrac{1}{2}\)
b: Ta có: \(\sqrt{45.8^2-44.2^2}-\sqrt{6\left[\left(\sqrt{2}+1\right)^2+\left(\sqrt{2}-1\right)^2\right]}\)
\(=12-\sqrt{6\cdot\left(3+2\sqrt{2}+3-2\sqrt{2}\right)}\)
=12-6
=6
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