a: Ta có: \(A=\dfrac{13}{3}\)
\(\Leftrightarrow3x+3\sqrt{x}+3=13\sqrt{x}\)
\(\Leftrightarrow3x-10\sqrt{x}+3=0\)
\(\Leftrightarrow\left(3\sqrt{x}-1\right)\left(\sqrt{x}-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{9}\\x=9\end{matrix}\right.\)
b: Ta có: \(A=\dfrac{\sqrt{x}}{8}\)
\(\Leftrightarrow x-2\sqrt{x}-24=0\)
\(\Leftrightarrow\left(\sqrt{x}-6\right)\left(\sqrt{x}+4\right)=0\)
hay x=36
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