a: \(A=\frac{13}{3}\)
=>\(\frac{x+\sqrt{x}+1}{\sqrt{x}}=\frac{13}{3}\)
=>\(3x+3\sqrt{x}+3=13\sqrt{x}\)
=>\(3x-10\sqrt{x}+3=0\)
=>\(\left(3\sqrt{x}-1\right)\left(\sqrt{x}-3\right)=0\)
=>\(\left[\begin{array}{l}3\sqrt{x}-1=0\\ \sqrt{x}-3=0\end{array}\right.\Rightarrow\left[\begin{array}{l}3\sqrt{x}=1\\ \sqrt{x}=3\end{array}\right.\Rightarrow\left[\begin{array}{l}\sqrt{x}=\frac13\\ \sqrt{x}=3\end{array}\right.\)
=>\(\left[\begin{array}{l}x=\frac19\left(nhận\right)\\ x=9\left(nhận\right)\end{array}\right.\)
b: \(A=\frac{\sqrt{x}}{8}\)
=>\(\frac{3}{\sqrt{x}-2}=\frac{\sqrt{x}}{8}\)
=>\(\sqrt{x}\left(\sqrt{x}-2\right)=24\)
=>\(x-2\sqrt{x}-24=0\)
=>\(\left(\sqrt{x}-6\right)\left(\sqrt{x}+4\right)=0\)
=>\(\sqrt{x}-6=0\)
=>\(\sqrt{x}=6\)
=>x=36(nhận)
