\(\sqrt{2x-5}-2\sqrt{3}=0\left(T\right)\)
ĐKXĐ: \(2x-5\ge0\Leftrightarrow x\ge\dfrac{5}{2}\)
\(\left(T\right)\Leftrightarrow\sqrt{2x-5}=2\sqrt{3}\)
\(\Leftrightarrow2x-5=12\)
\(\Leftrightarrow2x=17\)
\(\Leftrightarrow x=\dfrac{17}{2}\) ( thỏa mãn ĐK )
Vậy \(S=\left\{\dfrac{17}{2}\right\}\)
\(\sqrt{2x-5}-2\sqrt{3}=0\)
\(\Leftrightarrow2x-5=12\)
\(\Leftrightarrow2x=17\)
hay \(x=\dfrac{17}{2}\)

