Question

Answer 1

a)=\(\dfrac{3\left(1+\sqrt{7}\right)}{\left(1-\sqrt{7}\right)\left(1+\sqrt{7}\right)}\)=\(\dfrac{3\left(1+\sqrt{7}\right)}{1-7}\)=\(\dfrac{3\left(1+\sqrt{7}\right)}{-6}\)=\(\dfrac{-1-\sqrt{7}}{2}\)

b)\(\dfrac{\left(3-\sqrt{8}\right)\left(\sqrt{8}-3\right)}{\left(\sqrt{8}+3\right)\left(\sqrt{8}-3\right)}\)=\(\dfrac{3\sqrt{8}-9-8+3\sqrt{8}}{8-9}\)=\(\dfrac{6\sqrt{8}-17}{-1}\)=\(17-6\sqrt{8}\)

Answer 2

a: \(\dfrac{3}{1-\sqrt{7}}=\dfrac{-1-\sqrt{7}}{2}\)

b: \(\dfrac{3-\sqrt{8}}{3+\sqrt{8}}=17-12\sqrt{2}\)