a: \(\dfrac{6+2\sqrt{3}}{1+\sqrt{3}}+\dfrac{2-\sqrt{3}}{2+\sqrt{3}}\)
\(=\dfrac{2\sqrt{3}\left(\sqrt{3}+1\right)}{\sqrt{3}+1}+7-4\sqrt{3}\)
\(=2\sqrt{3}+7-4\sqrt{3}\)
\(=7-2\sqrt{3}\)
b: Ta có: \(\dfrac{\sqrt{21}-\sqrt{3}}{1-\sqrt{7}}+\dfrac{\sqrt{3}+1}{\sqrt{3}-1}\)
\(=\dfrac{-\sqrt{3}\left(1-\sqrt{7}\right)}{1-\sqrt{7}}+\dfrac{4+2\sqrt{3}}{2}\)
\(=-\sqrt{3}+2+\sqrt{3}\)
=2

