Question

Answer 1

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Answer 2

a) \(6x^3y-9x^2y^2+3xy\)

\(=3xy\left(2x^2-3xy+1\right)\)

b) \(x^2-3x+xy-3y\)

\(=\left(x^2-3x\right)+\left(xy-3y\right)\)

\(=x\left(x-3\right)+y\left(x-3\right)\\ =\left(x+y\right)\left(x-3\right)\)

 

Answer 3

c) \(x^2-y^2-4x+4y\)

\(=\left(x^2-y^2\right)-\left(4x-4y\right)\\ =\left(x-y\right)\left(x+y\right)-4\left(x-y\right)\\ =\left(x-y\right)\left(x+y-4\right)\)

Answer 4

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Answer 5

\(a,\)\(=3xy\left(2x^2-3xy+1\right)\)

b,\(=x\left(x-3\right)+y\left(x-3\right)=\left(x+y\right)\left(x-3\right)\)

c,\(=x^2+xy-2x-xy-y^2-2y-2x-2y+4\)

\(=x\left(x+y-2\right)-y\left(x+y-2\right)-2\left(x+y-2\right)\)

\(=\left(x-y-2\right)\left(x+y-2\right)\)

Answer 6

a) Ta có: \(6x^3y-9x^2y^2+3xy\)

\(=3xy\left(2x^2-3xy+1\right)\)

b) Ta có: \(x^2-3x+xy-3y\)

\(=x\left(x-3\right)+y\left(x-3\right)\)

\(=\left(x-3\right)\left(x-y\right)\)

Answer 7

c) Ta có: \(x^2-y^2-4x+4\)

\(=\left(x^2-4x+4\right)-y^2\)

\(=\left(x-2-y\right)\left(x-2+y\right)\)