a) Ta có: \(A=\dfrac{10^{10}+1}{10^{11}+1}\)
\(\Leftrightarrow10A=\dfrac{10^{11}+1+9}{10^{11}+1}=1+\dfrac{9}{10^{11}+1}\)
Ta có: \(B=\dfrac{10^9+1}{10^{10}+1}\)
\(\Leftrightarrow10B=\dfrac{10^{10}+1+9}{10^{10}+1}=1+\dfrac{9}{10^{10}+1}\)
Ta có: \(10^{11}+1>10^{10}+1\)
\(\Leftrightarrow\dfrac{9}{10^{11}+1}< \dfrac{9}{10^{10}+1}\)
\(\Leftrightarrow A< B\)
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