Câu 1:
\(\lim_{x\to-5}\frac{\sqrt{x+14}-3}{x^2+4x-5}\)
\(=\lim_{x\to-5}\frac{x+14-9}{\left(\sqrt{x+14}+3\right)\left(x+5\right)\left(x-1\right)}\)
\(=\lim_{x\to-5}\frac{x+5}{\left(\sqrt{x+14}+3\right)\left(x+5\right)\left(x-1\right)}\)
\(=\lim_{x\to-5}\frac{1}{\left(\sqrt{x+14}+3\right)\left(x-1\right)}=\frac{1}{\left(\sqrt{-5+14}+3\right)\left(-5-1\right)}=\frac{1}{6\cdot\left(-6\right)}=-\frac{1}{36}\)
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