Question

y+x²y+3x²+3

Answer 1

\(y+x^2y+3x^2+3=\left(y+x^2y\right)+\left(3x^2+3\right)=y\left(x^2+1\right)+3\left(x^2+1\right)=\left(x^2+1\right)\left(y+3\right)\)

Answer 2

\(y+x^2y+3x^2+3\)

\(=y\left(x^2+1\right)+3\left(x^2+1\right)\)

\(=\left(x^2+1\right)\left(y+3\right)\)