\(\Leftrightarrow\left(2x-1\right)\left(x+3\right)-x\left(x+3\right)=0\)
=>(x+3)(x-1)=0
=>x=-3 hoặc x=1
\(\text{x(x+3)= (2x-1)(x+3)}\)
\(\Leftrightarrow x^2+3x=2x^2+6x-x-3\)
\(\Leftrightarrow x^2+3x-2x^2-6x+x+3=0\)
\(\Leftrightarrow-x^2-2x+3=0\)
\(a=-1\)
\(b=-2\)
\(c=3\)
\(\Delta=b^2-4ac=\left(-2\right)^2-4.\left(-1\right).3=-3< 0\)
Vậy \(S=\varnothing\)