Question

x+(x+1)+(x+2)+....+(x+25)=1235

Answer 1

x+(x+1)+(x+2)+....+(x+25)=1235 

= \(\left(x+x+...+x\right)+\left(1+2+3+...+25\right)=1235\)

= \(26x+325=1235\)

=> \(26x=1235+325=1560\)

= \(26x=1560\)

=> x = 1560 : 26 = 60 

=> x = 60 

Answer 2

x + (x+1) + (x+2) + ...+ (x+25 ) = 1235

x + x + 1 + x + 2 +...+ x + 25 = 1235

(x + x + x +...+ x) +  (1 + 2 +...+ 25) = 1235

26x + 325 = 1235

26x = 1235 - 325 = 910

x=910:26=35

Answer 3

x + (x + 1) + (x + 2) + ..... + (x + 25) = 1235

=> x + x + 1 + x + 2 + .... + x + 25 = 1235

=> (x + x + x + ... + x) + (1 + 2 + 3 + .... + 25 ) = 1235

=> 26x + [ (25 + 1) x 25 : 2] = 1235

=> 26x + 325 = 1235

=> 26x = 1235 - 325

=> 26x = 910

=> x = 910 : 26

=> x = 35

Answer 4

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