x+(x+1)+(x+2)+...+(x+2010)=2029099
= (x+0)+(x+1)+(x+2)+...+(x+2010)=2029099
= (x+x+x+...+x)+(0+1+2+3+...+2010)=2029099
\(\downarrow\)
có (2010-0):1+1=2011 số x
0+1+2+3+...+2010=(2010+0).2011:2=2021055
= x2011 + 2021055 = 2029099
= x2011 = 2029099 - 2021055
= x2011 = 8044
= x = 8044 : 2011
= x = 4 \(\in\)N
Vậy x = 4
A= (1-1/2010) x (1- 2/2010) x (1- 3/2010) x.... x( 1- 2011/2010) =?
tìm x:
a. x+10/10 + x+10/11 + x+10/12 x+10/13 x+10/14
b.x+4/2010 x+3/2010 x+2/2010 x+1/2010
Tìm x:
a) x+(x+1)+(x+2)+...+200+201=401
b) x+(x+1)+(x+2)+...+2009+2010=2010
Tìm số nguyên x thoả mãn:x+(x+1)+(x+2)+…+(x+2009)+(x+2010)=2010
Tìm x thỏa mãn: x + (x + 1) + (x + 2) + … + 2009 + 2010 = 2010 A.-2010 B.-2008 C.0 D.-2009
Tìm x
x+(x+1)+(x+2)+...+2009+2010=2010
Bài 1: Tìm x biết:
1/ x + (x + 1) + (x + 2) + (x + 3) +.....+ (x + 2006) + 2007 = 2007
2/ x + (x + 1) + (x + 2) +...+ 199 + 200 + 201 = 401
3/ x + (x + 1) + (x + 2) +....+ 2009 + 2010 = 2010
Bn nào nhanh mik tick nha!!!
x + ( x + 1 ) + ( x + 2 ) + ... + 2009 + 2010 = 2010
1/x(x+1) +1/(x+1)(x+2) + 1/(x+2)(x+3) - 1/x = 1/2010
tìm x thuộc N biết rằng
a] x+[x+1]+[x+2]+...+[x+2010]=2029099
b] 2+4+6+8...+2x=2010
