Question

x+(x+1)+(x+2)+...+(x+100)=7450

Answer 1

\(\Rightarrow\)(x+x+x+...+x)+(1+2+..+100)=7450

\(\Rightarrow\)101x+(100+1)*100/2=7450

\(\Rightarrow\)101x+101*50=7450

\(\Rightarrow\)101x+5050=7450

\(\Rightarrow\)101x=7450-5050

\(\Rightarrow\)101x=2400

\(\Rightarrow\)x=2400/101

mik ra k chia hết

nhưng kb vs mik nha ,mik là A.R.M.Y

Answer 2

=> x+x+1+x+2+......+x+100 = 7450

=> 100x + 5050 = 7450

=> 100x = 7450 - 5050 = 2400

=> x = 2400 : 100 = 24

Vậy x = 24

Tk mk nha

Answer 3

x+(x+1)+(x+2)+.........+(x+100) = 7450

(x+x+x+............+x) + (1+2+.........+100) = 7450

100x + 5050 = 7450

100x = 7450 - 5050

100x = 2400

x = 2400 : 100

x = 24

Vậy x = 24

Answer 4

\(x+\left(x+1\right)\left(x+2\right)+...+\left(x+100\right)=7450\)

\(\Leftrightarrow\left(x+x+x+...+x\right)+\left(1+2+...+100\right)=7450\)

\(\Leftrightarrow100x+5050=7450\)

\(\Leftrightarrow100x=7450-5050=2400\)

\(\Leftrightarrow x=2400:100=24\)

Answer 5

bài này có 101x mà