`x ( x+ 1) = 2 ( 1 + x )`
`x ( x + 1 ) - 2 ( 1+x ) =0`
`( x + 1 ) ( x- 2 ) =0`
`=> `
`TH1 : x + 1=0`
`=> x =-1`
`TH2 : x -2=0`
`=> x =2`
Vậy : `x \in { -1 ;2 }`
1/x-1-x^3-x/x^2+1(x/x^2-2x+1-1/x^2-1)
[2/(x+1)^3.(1/x+1)+1/x^2+2x+1(1/x^2+1)]:x-1/x^3=x/x-1
(x/x^2-36-x-6/x^2+6x):2x-6/x^2+6x+x/6-x
giúp mik với ;-; mik cần gấp
giải phương trình:
a, 2x-5/x+5=3
b, 2/x-1=6/x+1
c, 2x+1/x-1=5(x-1)/x+1
d, x/x-1 - 2x/x2-1=0
e, 1/x-2 + 3=x-3/2-x
f, x+1/x-2 + x-1/x+2= 2(x2+2)/x2-4
g, x+2/x-2 + 1/x+2=x(x-5)/x2-4
h, 1/x+1 - 5/x+2=15/(x+1)(2-x)
i, x-1/x+2 - x/x-2= 5x-2/4-x2
giải phương trình:
a) 2/x+1 - 1/x-3= 3x-11/x^2-2x-3
b) 3/x-2 +1/x=-2/x.(x-2)
c) x-3/x+3 - 2/x-3=3x+1/9-x^2
d) 2/x+1 - 1/x-2=3x-5/x^2-x-2
e) x-2/x+2 + 3/x-2=x^2-11/x^2-4
f) x+3/x+1 + x-2/x=2
g) x+5/x-5 - x-5/x+5=20/x^2-25
h) x+4/x+1 + x/x-1=2x^2/x^2-1
i) x+1/x-1 - 1/x+1=x^2+2/x^2-1
Giải phương trình chứa ẩn ở mẫu:
a. (x+1)/(x-2) - (x-1)(x+2) = 2(x2 + 2)/(x2 - 4)
b. (2x+1)/(x-1) = 5(x-1)/(x+1)
c. (x-1)/(x+2) - (x)/(x-2) = (5x-2)/(4 - x2)
d. (x-2)/(2+x)-(3)/(x-2)= 2(x-11)/(x2 - 2)
e. (x-1)/(x+1)-(x2 + x - 2)/(x+1)= (x+1)/(x-1) - x - 2
f. (x+1)/(x-1)-(x-1)/(x+1)=(4)/(x2 - 1)
g. (3)/4(x-5) + (15)/(50-2x2)= - (7)/6(x+5)
h. (12)/(8+x3)= 1 + (1)/(x+2)
k. (x+25)/(2x2 - 50)-(x+5)(x2 - 5x)= (5-x)(2x2 + 10x)
Giải phương trình:
A) 1-x/x+1 +3 = 2x+3/x+1
B) (x+2)^2/2x-3 -1 = x^2-10/2x-3
C) 5x-2/2-2x + 2x-1/2 = 1 + x^2+x-3/x-1
D) 5-2x/3 - (x-1)(x+1)/1-3x = (x+2)(1-3x)/9x-3
E) x-3/x-2 + x-2/x-4 = -1
F) 1 + x/3-x = 5/(x+2)(3-x) + 2/x+2
G) x+1/x-1 - x-1/x+1 = 3x( 1 - x-1/x+1 )
H) 1-6x/x-2 + 9x-4/x+2 = x(3x-2)+1/x^2-4
I) 3x-1/x-1 - 2x+5/x+3 + 4/x^2+2x-3 = 1
Quy đồng mẫu các phân thức:
1) 7x-1/2x^2+6x; 3-2x/x^2-9
2) 2x-1/x-x^2; x+1/2-4x+2x^2
3) x-1/x^3+1; 2x/x^2-x+1; 2/x+1
4) 7/5x; 4/x-2y; x-y/8y^2-2x^2
5) x/x^3-1; x+1/x^2-x; x-1/x^2+x+1
6) x/x^2-2ax+a^2; x+a/x^2-ax
Rút gọn
a) \((\dfrac{2x^2+3x}{x^3+1}+\dfrac{1}{x^2-x+1}).\dfrac{x^2-x+1}{x}\)
b) \(\left(\dfrac{1}{x-1}-\dfrac{1}{x}\right):\left(\dfrac{x+1}{x-2}-\dfrac{x+2}{x-1}\right)\)
c) \(\left(\dfrac{1}{x}+\dfrac{x}{x+1}\right).\dfrac{x^2+x}{x}\)
a, (3x+2)2 - (3x-2)2 =5x+38 b, 3(x-2)2 +9(x-1) =3(x2+x-3)
c, (x+3)3 -(x-3)2 -(x-3)2 =6x+18 d, (x-1)3-x(x+1)2=5x(2-x)-11(x+2)
e, (x+1)(x2-x+1)-2x=x(x-1)(x+1) f, (x-2)3+(3x-1)(3x+1)=(x+1)3
giải phương trình |x+1|+|x-1|=1+|x^2-1|giải phương trình |x+1|+|x-1|=1+|x^2-1|giải phương trình |x+1|+|x-1|=1+|x^2-1|giải phương trình |x+1|+|x-1|=1+|x^2-1|giải phương trình |x+1|+|x-1|=1+|x^2-1|
Giải phương trình sau
C x-2/c+2+3/x-2=x^2-11/x^2-4
D 2/x+1-1/x-2=3x-11/(x+1)(x-2)
E x+3/x-2-1/x=2/x^2+2x
F x+2/x-2-1/x=2/x(x-2)
G 3x-1/x-1-2x+5/x-3=1
H 2x/2x-1+x/2x+1=1+4/(2x-1)(2x+1)
