Có: \(n_{CH_3COOC_2H_5}=\dfrac{17,6}{88}=0,2\left(mol\right)\)
PT: \(CH_3COOC_2H_5+NaOH\underrightarrow{t^o}CH_3COONa+C_2H_5OH\)
__________0,2______________________________0,2 (mol)
\(\Rightarrow m_{C_2H_5OH}=0,2.46=9,2\left(g\right)\)
Bạn tham khảo nhé!