\(\frac{x}{5}=\frac{y}{3}=\frac{z}{2}\)
\(\Rightarrow\frac{2x}{2.5}=\frac{3y}{3.3}=\frac{z}{2}\)
\(\Rightarrow\frac{2x}{10}=\frac{3y}{9}=\frac{2x-3y}{10-9}=\frac{100}{1}=100\)
Ta có: \(\frac{2x}{10}=\frac{x}{5}=100\)\(\Rightarrow x=500\)
\(\frac{3y}{9}=\frac{y}{3}=100\Rightarrow y=300\)
\(\frac{z}{2}=100\Rightarrow z=200\)
Vậy x = 500, y = 300 và z = 200