4x+4(3x+2x)=0
4x+12x+8x=0
24x=0
x=0:24
x=0
Vậy x=0
\(x^4+4\left(x^3+x^2\right)=0\)
\(\Leftrightarrow x^4+4x^3+4x^2=0\)
\(\Leftrightarrow\left(x^4+2x^3\right)+\left(2x^3+4x^2\right)=0\)
\(\Leftrightarrow x^3\left(x+2\right)+2x^2\left(x+2\right)=0\)
\(\Leftrightarrow x^2\left(x+2\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)
\(\Leftrightarrow x^4+4x^3+4x^2=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)