Ta có: \(\frac{x+41}{51}+\frac{x+32}{52}=\frac{x+23}{53}+\frac{x+14}{54}\)
=>\(\left(\frac{x+41}{51}+9\right)+\left(\frac{x+32}{52}+9\right)=\left(\frac{x+23}{53}+9\right)+\left(\frac{x+14}{54}+9\right)\)
=>\(\frac{x+500}{51}+\frac{x+500}{52}=\frac{x+500}{53}+\frac{x+500}{54}\)
=>\(\left(x+500\right)\left(\frac{1}{51}+\frac{1}{52}-\frac{1}{53}-\frac{1}{54}\right)=0\)
=>x+500=0
=>x=-500