Câu hỏi của Nguyen Ngoc Linh

Question

x3 + 1        x3 - 1              x3 - 8              x3 + 8        27 - x3

Nguyễn Lê Phước Thịnh · Accepted Answer

$x^3+1=\left(x+1\right)\left(x^2-x+1\right)$$x^3-1=\left(x-1\right)\left(x^2+x+1\right)$$x^3-8=\left(x-2\right)\left(x^2+2x+4\right)$$x^3+8=\left(x+2\right)\left(x^2-2x+4\right)$$27-x^3=\left(3-x\right)\left(9+3x+x^2\right)$Câu trả lời: $x^3+1=\left(x+1\right)\left(x^2-x+1\right)$$x^3-1=\left(x-1\right)\left(x^2+x+1\right)$$x^3-8=\left(x-2\right)\left(x^2+2x+4\right)$$x^3+8=\left(x+2\right)\left(x^2-2x+4\right)$$27-x^3=\left(3-x\right)\left(9+3x+x^2\right)$

⭐Hannie⭐ · Answer

$x^3 + 1$$=
(
x
+
1
)
(
x
^2
−
x
+
1
)$$ x^3 - 1    =(x-1)(x^2+x+1)$$x^3 - 8  =(x-2)(x^2+2x+4)$$ x^3 + 8=(x+2)(x^2-2x+4)$$ 27 - x^3=
(
3
−
x
)
(
9
+
3
x
+
x
^2
)$Câu trả lời: $x^3 + 1$$=
(
x
+
1
)
(
x
^2
−
x
+
1
)$$ x^3 - 1    =(x-1)(x^2+x+1)$$x^3 - 8  =(x-2)(x^2+2x+4)$$ x^3 + 8=(x+2)(x^2-2x+4)$$ 27 - x^3=
(
3
−
x
)
(
9
+
3
x
+
x
^2
)$

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