\(x\left(2x-3\right)-4x^2+9=0\)
\(x\left(2x-3\right)-\left(4x^2-9\right)=0\)
\(x\left(2x-3\right)-\left[\left(2x\right)^2-3^2\right]=0\)
\(x\left(2x-3\right)-\left(2x-3\right)\left(2x+3\right)=0\)
\(\left(2x-3\right)\left(x-2x-3\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x=3\\-x=3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-3\end{matrix}\right.\)
Vậy x = 3/2 hoặc x = -3
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