\(x\left(2x-1\right)\left(x+3\right)=0\)
\(\Leftrightarrow x=0\) hoặc \(2x-1=0\) hoặc \(x+3=0\)
*) \(2x-1=0\)
\(2x=1\)
\(x=\dfrac{1}{2}\)
*) \(x+3=0\)
\(x=-3\)
Vậy \(S=\left\{-3;0;\dfrac{1}{2}\right\}\)
\(x\left(2x-1\right)\left(x-3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\2x-1=0\\x-3=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\2x=1\\x=3\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{2}\\x=3\end{matrix}\right.\)