\(\text{Δ}=5^2-4\cdot1\cdot\left(3m-1\right)=25-12m+4=-12m+29\)
Để phương trình có hai nghiệm thì Δ>=0
=>-12m+29>=0
=>-12m>=-29
=>\(m< =\dfrac{29}{12}\)
Theo Vi-et, ta có:
\(\left\{{}\begin{matrix}x_1+x_2=-\dfrac{b}{a}=-5\\x_1x_2=\dfrac{c}{a}=3m-1\end{matrix}\right.\)
\(x_1+x_2+3x_1x_2=75\)
=>\(-5+3\left(3m-1\right)=75\)
=>3(3m-1)=80
=>9m-3=80
=>9m=83
=>\(m=\dfrac{83}{9}\)(loại)