Question

(x−2)×(2x2+x−1)−2x×(x2−3/2x)=22     giúp mik vs

Answer 1

\(\Leftrightarrow2x^3+x^2-x-4x^2-2x+2-2x^3+3x^2=22\)

=>-3x=20

hay x=-20/3

Answer 2

(x - 2) x (2x2 + x - 1) - 2x . (x2 - 3/2x ) =22

=> 2x³ + x² - x - 4x² - 2x + 2 - 2x³ + 3x² = 22

=> - 3x = 20

hay x = - 20/3

vậy x = [20/3 ; - 20/3]

Answer 3

`(x - 2) xx ( 2x^2 + x - 1) - 2x xx ( x^2 - 3/2x) = 22`

`2x^3 + x^2 - x - 4x^2 - 2x + 2 - 2x^3 + 3x^2 = 22`

` (2x^3 - 2x^3) + (x^2 - 4x^2 + 3x^2) + ( -x - 2x ) + 2 =22`

` -3x + 2 = 22`

`-3x = 11`

`x = 11 : (-3)`

`x = -11/3`

Answer 4

$\iff 2{}^{}+{}^{}-x-4{}^{}-2x+2-2{}^{}+3{}^{}=22$

=>-3x=20

hay x=-20/3

Answer 5

(x - 2) x (2x2 + x - 1) - 2x . (x2 - 3/2x ) =22

=> 2x³ + x² - x - 4x² - 2x + 2 - 2x³ + 3x² = 22

=> - 3x = 20

hay x = - 20/3

vậy x = [20/3 ; - 20/3]

Answer 6

$(x-2)\times (2{}^{}+x-1)-2x\times ({}^{}-\frac{3}{2}x)=22$

$2{}^{}+{}^{}-x-4{}^{}-2x+2-2{}^{}+3{}^{}=22$

$(2{}^{}-2{}^{})+({}^{}-4{}^{}+3{}^{})+(-x-2x)+2=22$

$-3x+2=22$