\(TH1\\ \left(x+2\right)^2=5^2\\ x+2=5\\ x=3\\ TH2\\ \left(x+2\right)^2=\left(-5\right)^2\\ x+2=-5\\ x=-7\)
=>x+2=5 hoặc x+2=-5
=>x=3 hoặc x=-7
( x + 2 )2 = 25
( x + 2 )2 = \(\pm\) 52
\(\Rightarrow x+2=\pm5\Rightarrow\left[{}\begin{matrix}x+2=5\\x+2=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\x=-7\end{matrix}\right.\)