x/2+x+x/3+x+x+x/4=23/4
⇒ 6x/12+12x/12+4x/12+12x/12+12x/12+3x/12=23/4
⇒ (6x+12x+4x+12x+12x+3x)/12=23/4
⇒ 49x/12=23/4
⇒ 49x=23/4.12
⇒ 49x=69
⇒ x=69/49
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Giải:
\(\dfrac{x}{2}+x+\dfrac{x}{3}+x+x+\dfrac{x}{4}=\dfrac{23}{4}\)
\(x.\left(\dfrac{1}{2}+1+\dfrac{1}{3}+1+1+\dfrac{1}{4}\right)=\dfrac{23}{4}\)
\(x.\dfrac{49}{12}=\dfrac{23}{4}\)
\(x=\dfrac{23}{4}:\dfrac{49}{12}\)
\(x=\dfrac{69}{49}\)
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