Câu hỏi của Lizy

Question

$x^2 +5x-6$$5x^2 +5xy-x-y$$7x-6x^2 -2$Phân tích thành nhân tử

GV Nguyễn Trần Thành Đạt · Accepted Answer

$x^2+5x-6\
=x^2-x+6x-6\
=x\left(x-1\right)+6\left(x-1\right)\
=\left(x+6\right)\left(x-1\right)\
---\
5x^2+5xy-x-y\
=x\left(5x-1\right)+y\left(5x-1\right)\
=\left(5x-1\right)\left(x+y\right)\
----\
7x-6x^2-2\
=-6x^2+3x+4x-2\
=-3x\left(2x-1\right)+2\left(2x-1\right)\
=\left(2-3x\right)\left(2x-1\right)$Câu trả lời: $x^2+5x-6\
=x^2-x+6x-6\
=x\left(x-1\right)+6\left(x-1\right)\
=\left(x+6\right)\left(x-1\right)\
---\
5x^2+5xy-x-y\
=x\left(5x-1\right)+y\left(5x-1\right)\
=\left(5x-1\right)\left(x+y\right)\
----\
7x-6x^2-2\
=-6x^2+3x+4x-2\
=-3x\left(2x-1\right)+2\left(2x-1\right)\
=\left(2-3x\right)\left(2x-1\right)$

Hà Quang Minh · Answer

$x^2+5x-6=\left(x-1\right)\left(x+6\right)\
5x^2+5xy-x-y=\left(5x-1\right)\left(x+y\right)\
7x-6x^2-2=\left(3x-2\right)\left(2x-1\right)$Câu trả lời: $x^2+5x-6=\left(x-1\right)\left(x+6\right)\
5x^2+5xy-x-y=\left(5x-1\right)\left(x+y\right)\
7x-6x^2-2=\left(3x-2\right)\left(2x-1\right)$

Khoá học trên OLM (olm.vn)

Khoá học trên OLM (olm.vn)