Question

(x²-4x+3):(x-3)

Answer 1

\(=\dfrac{\left(x-3\right)\left(x-1\right)}{x-3}=x-1\)

Answer 2

\(\left(x^2-x-3x+3\right):\left(x-3\right)=\left[x\left(x-1\right)-3\left(x-1\right)\right]:\left(x-3\right)=\dfrac{\left(x-1\right)\left(x-3\right)}{x-3}=x-1\)