Question

x^2 -4x+3=0

Answer 1

`x^2 -4x+3=0`

`<=> x^2 -3x-x+3=0`

`<=> x(x-3)-(x-3)=0`

`<=>(x-3)(x-1)=0`

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x-1=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

Answer 2

\(x^2-4x+3=0\\ \Leftrightarrow x^2-x-3x+3=0\\ \Leftrightarrow x\left(x-1\right)-3\left(x-1\right)=0\\ \Leftrightarrow\left(x-1\right)\left(x-3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-1=0\\x-3=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=3\end{matrix}\right.\)

Answer 3

`x^2 -4x+3=0`

`<=>(x-3)(x-1)=0`

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

Answer 4

từ s'đã

Answer 5

${}^{}-4x+3=0$

$\iff {}^{}-3x-x+3=0$

$\iff x(x-3)-(x-3)=0$

$\iff (x-3)(x-1)=0$

⇔[x−3=0x−1=0⇔[x−3=0x−1=0

⇔[x=3x=1