Question

( \(x^2\) - 4 ) . ( 2x +10 ) =0

 

Answer 1

=>(x-2)(x+2)(x+5)=0

hay \(x\in\left\{2;-2;-5\right\}\)

Answer 2

`(x^2 -4).(2x+10)=0`

`=> (x-2)(x+2)(2x+10)=0`

\(\Rightarrow\left[{}\begin{matrix}x-2=0\\x+2=0\\2x+10=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=0+2\\x=0-2\\2x=-10\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-2\\x=-5\end{matrix}\right.\)