Question

x^2 + 36x -10 = 0

Answer 1

\(\Leftrightarrow x^2+36x+324-334=0\)

\(\Leftrightarrow\left(x+18\right)^2=334\)

hay \(x\in\left\{\sqrt{334}-18;-\sqrt{334}-18\right\}\)

Answer 2

\(x^2+36x-10=0\\ \Leftrightarrow x\left(x+26\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=-26\end{matrix}\right.\)