Question

(x²-1)(2x+3)=(x²-1)(3x+2)

Cíu vs

Answer 1

\(\left(x^2-1\right)\left(2x+3\right)=\left(x^2-1\right)\left(3x+2\right)\)

\(\Leftrightarrow\left(x^2-1\right)\left(2x+3\right)-\left(x^2-1\right)\left(3x+2\right)=0\)

\(\Leftrightarrow\left(x^2-1\right)\left(2x+3-3x-2\right)=0\)

\(\Leftrightarrow\left(x^2-1\right)\left(-x+1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)

Vậy....

Answer 2

=> ( x² -1 )( 2x +3) - ( x² - 1)( 3x +2 ) =0

=> (x² - 1). ( 2x +3 - 3x - 2) =0

=> ( x²- 1)( 1-x) = 0

=> x² - 1 =0 hoặc 1 - x =0

=> x= 1

Answer 3

Bài làm

\(\left(x^2-1\right)\left(2x+3\right)=\left(x^2-1\right)\left(3x+2\right)\)

\(\Leftrightarrow\left(x^2-1\right)\left(2x+3\right)-\left(x^2-1\right)\left(3x+2\right)=0\)

\(\Leftrightarrow\left(x^2-1\right)\left(2x+3-3x-2\right)=0\)

\(\Leftrightarrow\left(x^2-1\right)\left(-x+1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-1\\x=-1\end{cases}}\)