Question

x+1/x+2=0,8/1,2.     tìm x

Answer 1

\(\frac{x+1}{x+2}=\frac{0,8}{1,2}\)

\(\Rightarrow\frac{x+1}{x+2}=\frac{2}{3}\)

Để \(\frac{x+1}{x+2}=\frac{2}{3}\)

<=> (x+1).3=(x+2).2

=>    3x+3.1=2x+2.2

=>    3x+3   =2x+4

=>    3x-2x  =4-3

=>    (3-2).x  =1

=>     x         =1    

Vậy x=1

Chúc các bạn học tốt

Answer 2

x+1x+2 =0,81,2 

⇒x+1x+2 =23 

Để x+1x+2 =23 

<=> (x+1).3=(x+2).2

=>    3x+3.1=2x+2.2

=>    3x+3   =2x+4

=>    3x-2x  =4-3

=>    (3-2).x  =1

=>     x         =1    

Vậy x=1

Answer 3

x = 1

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Answer 4

\(\frac{x+1}{x+2}=x+\frac{1}{2}=\frac{0,8}{1,2}\)

\(\Rightarrow\)x =1

Answer 5

\(\frac{x+1}{x+2}=\frac{0,8}{1,2}\Leftrightarrow\frac{x+1}{x+2}=\frac{2}{3}\)

Áp dụng t/c tỉ lệ thức : \(\frac{a}{b}=\frac{c}{d}\Leftrightarrow ad=bc\)

Ta có: \(\left(x+1\right).3=\left(x+2\right).2\)

\(\Rightarrow3x+3=2x+4\Rightarrow3x-2x=4-3\Rightarrow x=1\)

Vậy x=1