b: =>2|3x+1|=18
=>|3x+1|=9
\(\Leftrightarrow\left[{}\begin{matrix}3x+1=9\\3x+1=-9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=-\dfrac{10}{3}\end{matrix}\right.\)
\(\left(\dfrac{-2}{3}\right)^2.x=\left(\dfrac{-2}{3}\right)^5\)
\(\left(x-\dfrac{1}{2}\right)^3=\dfrac{1}{27}\)
\(\left(\dfrac{2}{3}x-1\right)\left(\dfrac{3}{4}x+\dfrac{1}{2}\right)=0\)
\(\dfrac{4}{9}:x=3\dfrac{1}{3}:2,25\)
\(1\dfrac{1}{3}:0,8=\dfrac{2}{3}:0,1x\)
\(\left(3-x\right)^3=-\dfrac{27}{64};\left(x-5\right)^3=\dfrac{1}{-27};\left(x-\dfrac{1}{2}\right)^3=\dfrac{27}{8};\left(2x-1\right)^2=\dfrac{1}{4};\left(2-3x\right)^2=\dfrac{9}{4};\left(1-\dfrac{2}{3}\right)^2=\dfrac{4}{9}\)
\(x^2-19=5.9;\left(2x+1\right)^3=-0,001;\left(\dfrac{5}{6}\right)^{2x-1}=\left(\dfrac{5}{6}\right)^5;\left(\dfrac{1}{3}x-\dfrac{2}{3}\right)^3=27;\left(\dfrac{1}{32}\right)^x=\left(\dfrac{1}{2}\right)^{15}\)
a,2.(\(\dfrac{1}{4}\)+x)\(^3\)=(\(-\dfrac{27}{4}\))
b,(x+\(\dfrac{1}{2}\))\(^3\):3=\(\dfrac{-1}{81}\)
c,(\(\dfrac{2}{3}\)-x)\(^2\)=1:\(\dfrac{4}{9}\)
d,(2x-\(\dfrac{1}{5}\))\(^2\)+\(\dfrac{16}{25}\)=1
e,(\(\dfrac{2}{5}\)-3x)\(^2\)-\(\dfrac{1}{5}\)=\(\dfrac{4}{25}\)
a)\([x.\dfrac{1}{2}]^{3}=\dfrac{1}{27}\)
b)\([x+\dfrac{1}{2} ]^{2}=\dfrac{4}{5} \)
c) I 3x-4/5 I = 11/5
d) I 2x - 2I = 0
Tìm x:
a) \(\dfrac{-12}{17}\) < \(\dfrac{x}{17}\) < \(\dfrac{-8}{17}\)
b) \(\dfrac{-1}{2}< x< \dfrac{5}{3}\)
c) 3,456 < x \(\le\) 7,89
d) 5,82 < \(\overline{\text{5,8x0}}\) < 5,845
e) 32, 82 < \(\overline{\text{3x, 850}}\) < 35,845
a) (2x-1)^3=27
b) (2x-1)^4=81
c) (x-2)^5=-32
d) (3x-1)^4=(3x-1)^6
đ) 5^x +5^x+2=650
g) 3^x-1 +5.3^x-1=162
Bài 1:Tìm x
a, \(\dfrac{x}{6}=\dfrac{7}{3}\)
b,\(\dfrac{20}{x}=\dfrac{-12}{15}\)
c,\(\dfrac{-15}{35}=\dfrac{27}{x}\)
d,\(\dfrac{\dfrac{4}{5}}{1\dfrac{2}{5}}=\dfrac{2\dfrac{2}{5}}{x}\)
e,\(\dfrac{x}{1\dfrac{1}{4}}=\dfrac{1\dfrac{1}{5}}{2}\)
f,\(\dfrac{\dfrac{1}{2}}{1\dfrac{1}{4}}=\dfrac{x}{3\dfrac{1}{3}}\)
Bài 2:Tìm x
a,\(3x:2,7=\dfrac{1}{3}:2\dfrac{1}{4}\)
b,\(3:0,4x=1:0,01\)
c,\(4,5:0,3=2,25:0,1x\)
d,\(x:27=-2:3,6\)
Bài 3:Tìm x
a,\(1,35:0,2=1,25:0,1x\)
b,\(3,8:2x=\dfrac{1}{4}:2\dfrac{2}{3}\)
c,\(3\dfrac{1}{3}:2,4=0,35x:0,35\)
d,\(1\dfrac{1}{3}:0,8=\dfrac{2}{3}:0,1x\)
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