Các câu hỏi tương tự
Tìm x :
a) x (3x + 1) + (x -1)2 - (2x + 1)(2x -1) = 0
b) (x + 1)3 + (2 - x)3 - 9(x - 3)(x+3) = 0
c) (x - 1)3 - (x + 3)(x2 - 3x + 9) + 3x2 = 25
d) (x + 2)3 - ( x +1)(x2 - x + 1) - 6(x - 1)2 = 23
e) (x + 3)(x2 - 3x + 9) - x(x - 2)(x+2) + 11 = 0
f) x(x - 3) - x + 3 = 0
Bài 2: Tìm x biết:1,x^2+4x+4252,(5-2x)^2-1603,(x-3)^3-(x-3)(x^2+3x+9)+9(x+1)^2154,3(x+2)^2+(2x-1)^2-7(x-3)9x+3)365,(x-3)(x^2+3x+9)+x(x+2)(2-x)16,(2x+1)^2-4(x+2)^297,(x+3)^{^{ }2}-(x-4)(x+8)1
Đọc tiếp
Bài 2: Tìm x biết:
1,x\(^2\)+4x+4=25
2,(5-2x)\(^2\)-16=0
3,(x-3)\(^3\)-(x-3)(x\(^2\)+3x+9)+9(x+1)\(^2\)=15
4,3(x+2)\(^2\)+(2x-1)\(^2\)-7(x-3)9x+3)=36
5,(x-3)(x\(^2\)+3x+9)+x(x+2)(2-x)=1
6,(2x+1)\(^2\)-4(x+2)\(^2\)=9
7,(x+3)\(^{^{ }2}\)-(x-4)(x+8)=1
a, [(x/x^2-25) - (x-5/X^2+5x)] : (2x-5/x^2+5x) + ( x/ 5-x)
b, [(9/x^3-9x) + (1/x+3)] : [(x-3/x^2+ 3x) - ( x/3x+9)]
c, (1/x-1) - (x^3-x/x^2+1) . [(x/x^2+1-2x) + (1/1-x^2)]
bài 1
a)(x-1)(x+2)-(x-3)(x+1)=5x-3
b)(2x-1)(x+3)-(x-2)(x+2)=3x+1
c)x^2(x-1)-x(x-1)(x+1)=0
d)4x(x-5)-(2x-3)(2x+3)=9
Bài 3.
1.A=(x-3).(x+3)+15-x^2
2. B=(x-1).(x^2+x+1)-x.(x^2+2)+2x
3. C=92x-1).(4x^2+2x+1 ) -x.(8x2 +1)+x
4.(2x-3).(4x^2+6x+9)-2x.(4x^2-1)=2x-27
5. (x-3).(x^2+3x+9)=x^3-27
ghi rõ cách làm nha
Các bạn giúp mình với !!!
a,(3x-1)2+(x+3)2-10(x+1)(x-1)=0
b,(x+3)3+(2x+1)(4x2-2x+1)-9x2(x+1)=54
c,(x-3)3-(x-3)(x2+3x+9)+9(x+1)2=-33
P)(9-x)(x^2+2x-3) n)(-x+3)(x^2+x+1) O)(-6x+1/2)(x^2-4x+2) q)(6x+1)(x^2-2x-3) r)(2x+1)(-x^2-3x+1) U)(2x-3)(-x^2+x+6) s)(-4x+5)(x^2+3x-2) V)(-1/2x+3)(2x+6-4x^3)
1: 3/x+1 + 2/x+2 = 5x+4/x2+ 3x + 2
2: 2/3x + 1 - 15/6x2-x-1 = 3/2x - 1
3: 9/3x - 1 - 5-x/3x2-4x+1 = 4/x+ 1
4:5/x - 2 + 2/x+4 = 3x/x2 + 2x - 8
5: 4/x+6 + 1/x - 3 = 9/x2 + 3x - 18
6:x/x-3 - 2x2 +9/2x2 - 3x - 9= 1/2x + 3
Tìm x biết :
a) x^2 - 3x + 2 (x-3) = 0
b) (x-1)(x+1) + x (x-9) = 2x^2 - 4
c) x (x-3) - 3x + 9 = 0
d) x (x+2) - (x-3)(x+3) = 5
đ) 2x (x+1) - (2x+1)(x-3) = 6
Giải phương trình
a) 2x-1/x+1 = -2x+1/x-5
b) 1/x-3 + 2/x^2-9 = x/x^2-2x-3