Question

x+1/3=y+2/-4=z-3/5 và 5x+y+2z=42

Answer 1

\(\frac{x+1}{3}=\frac{y+2}{-4}=\frac{z-3}{5}\Leftrightarrow\frac{5x+5}{15}=\frac{y+2}{-4}=\frac{2z-6}{10}\)

ADTCDTS=nhau ta có

\(\frac{5x+5}{15}=\frac{y+2}{-4}=\frac{2z-6}{10}=\frac{\left(5x+5\right)+\left(y+2\right)+\left(2z-6\right)}{15+-4+10}\)

\(=\frac{5x+5+y+2+2z-6}{11}=\frac{\left(5x+y+2z\right)+\left(5+2-6\right)}{11}\)

=\(\frac{43+\left(5+2-6\right)}{11}=\frac{43+1}{11}=\frac{44}{11}=4\)

\(\Rightarrow\frac{x+1}{3}=4\Rightarrow x+1=12\Rightarrow x=11\)

\(\frac{y+2}{-4}=4\Rightarrow y+2=-16\Rightarrow y=-18\)

\(\frac{z-3}{5}=4\Rightarrow z-3=20\Rightarrow z=23\)

TỰ KẾT LUẬN NHA CÁC BAN:D