\(x+\dfrac{1}{3}=\dfrac{1}{2}:\dfrac{5}{4}+\dfrac{10}{7}\)
\(x+\dfrac{1}{3}=\dfrac{2}{5}+\dfrac{10}{7}\)
\(x=\dfrac{2}{5}+\dfrac{10}{7}-\dfrac{1}{3}\)
\(x=\dfrac{157}{105}\)
\(\Leftrightarrow x+\dfrac{1}{3}=\dfrac{1}{2}\cdot\dfrac{4}{5}+\dfrac{10}{7}=\dfrac{2}{5}+\dfrac{10}{7}=\dfrac{64}{35}\)
=>x=157/105